#_*_ coding=utf-8
__author__ = 'kysida'
#定义函数
def leap_year(year):
if year % 4 == 0:
if (year / 100) % 4 == 0:
return "the year is a leap year"
return "the year is not a leap year"
#主程序
if __name__ == '__main__':
year = int(raw_input("Please input the year:"))
print leap_year(year)转载于:https://blog.51cto.com/hongtengfei/1748009
